0、引言
在开发的过程中,很多业务场景需要一个树形结构的结果集进行前端展示,也可以理解为是一个无限父子结构,常见的有报表指标结构、菜单结构等。Java中递归实现树形结构的两种常见方式如下:
- Java7及以下纯Java递归实现
- Java8及以上借助lamda表达式实现
1、数据准备
Java实体类NodePO对应数据库表
package com.wbs.pojo;
import lombok.Data;
import lombok.NoArgsConstructor;
import java.util.List;
@Data
@NoArgsConstructor
public class NodePO {
/**
* 当前节点id
*/
private String id;
/**
* 当前节点名称
*/
private String name;
/**
* 父级节点id
*/
private String parentId;
/**
* 当前节点序号
*/
private String orderNo;
/**
* 子集节点
*/
private List children;
/**
* 构造函数
* @param id
* @param name
* @param parentId
* @param orderNo
*/
public NodePO(String id,String name,String parentId,String orderNo){
this.id = id;
this.name = name;
this.parentId = parentId;
this.orderNo = orderNo;
}
}
自己造一些数据模拟从数据库中查询出来的数据:
static final List nodePOs = Arrays.asList(
new NodePO("1","一级节点1",null,"_0001"),
new NodePO("2","二级节点1.1","1","_0002"),
new NodePO("3","二级节点1.2","1","_0003"),
new NodePO("4","一级节点2",null,"_0004"),
new NodePO("5","二级节点2.1","4","_0005"),
new NodePO("6","二级节点2.2","4","_0006"),
new NodePO("7","三级节点2.2.1","6","_0007"),
new NodePO("8","一级节点3",null,"_0008"),
new NodePO("9","二级节点3.1","8","_0009"),
new NodePO("10","三级节点3.1.1","9","_0010"),
new NodePO("11","四级节点3.1.1.1","10","_0011"),
new NodePO("12","五级节点3.1.1.1.1","11","_0012")
);
2、类型转化
从开发的过程中发现直接操作实体类集合,专门指定某一个实体类封装的方法是不具有普适性的,所以将实体类集合统一转化为Map集合,操作方便,具有一定的普适性:
List
BeanMapUtils自己简单封装一个工具类(不惧普适性勿喷):
package com.wbs.util;
import com.alibaba.fastjson.JSON;
import com.alibaba.fastjson.JSONObject;
import com.google.common.collect.Lists;
import com.google.common.collect.Maps;
import lombok.SneakyThrows;
import org.springframework.cglib.beans.BeanMap;
import java.util.*;
import java.util.function.Function;
import java.util.stream.Collectors;
/**
* @author 一宿君
* @version Id: BeanMapUtils.java, v 0.1 Administrator Exp $$
* @date 2022-10-13 14:24:20
* @desc java实体类和map相互转换工具类
*/
public class BeanMapUtils {
/**
* 将实体类对象属性转化为map对象
* @param t
* @param
* @return
*/
public static Map beanToMap(T t) {
Map map = new HashMap();
if (t != null) {
if (t instanceof JSONObject){
return (JSONObject)t;
}
BeanMap beanMap = BeanMap.create(t);
for (Object key : beanMap.keySet()) {
map.put(key.toString(), beanMap.get(key));
}
}
return map;
}
/**
* 将map对象中转化为实体类对象
* @param map
* @param clazz
* @param
* @return
* @throws Exception
*/
public static T mapToBean(Map map,Class clazz) throws Exception {
T bean = clazz.newInstance();
if (bean instanceof JSONObject){
JSONObject jsonObject = (JSONObject)bean;
Set
其中org.springframework.cglib.beans.BeanMap;是org.springframework:spring-core依赖下的工具包,spring-core核心依赖只要导入spring-boot-starter依赖即可
org.springframework.bootspring-boot-starter2.2.0.RELEASE

3、递归实现方法
3.1、Java7及以下纯Java递归实现
既然是Java7及以下实现方式,那排序也用最原始的冒泡排序:
/**
* 冒泡排序,小的在前,大的在后
* @param list
* @return
*/
public static List> sortJava7Map(List> list){
if(CollectionUtils.isEmpty(list)){
return Lists.newArrayList();
}
boolean flag;
int size = list.size();
for (int i = 0; i frontMap = list.get(j - 1);
Map afterMap = list.get(j);
if (String.valueOf(frontMap.get("orderNo")).compareTo(String.valueOf(afterMap.get("orderNo"))) > 0){
list.set(j - 1,afterMap);
list.set(j,frontMap);
flag = true;
}
}
//如果没有发生位置互换,则退出循环
if (!flag){
break;
}
}
return list;
}
给定一个节点,获取它的所有子节点:
/**
* Java7及以下版本获取子节点的方式
* @param parentNode
* @param allList
* @return
*/
public static List> getJava7Children(Map parentNode,List> allList){
//存放当前节点的直系子节点
List> curNodeChildrenList = Lists.newArrayList();
//存放直系子节点以外的节点
List> otherNodeList = Lists.newArrayList();
Object pId = parentNode.get("id");
for (Map map : allList) {
Object curPId = map.get("parentId");
if (ObjectUtils.isNotEmpty(curPId) && Objects.equals(pId,curPId)){
curNodeChildrenList.add(map);
}else {
otherNodeList.add(map);
}
}
if (curNodeChildrenList.isEmpty()){
return curNodeChildrenList;
}
//每一层级都进行排序
curNodeChildrenList = sortJava7Map(curNodeChildrenList);
//迭代直系子节点再获取子节点
for (Map map : curNodeChildrenList) {
map.put("children",getJava7Children(map,otherNodeList));
}
return curNodeChildrenList;
}
给出一个结果集,构建树形结果集:
/**
* 使用Java7的方式获取树形结构
* @param allList
* @return
*/
public static List> getJava7ResultTree(List> allList){
//存放所有的一级节点
List> oneLevelNodeList = Lists.newArrayList();
for (Map map : allList) {
if (ObjectUtils.isEmpty(map.get("parentId"))){
map.put("children",getJava7Children(map,allList));
oneLevelNodeList.add(map);
}
}
return sortJava8Map(oneLevelNodeList);
}
获取树形结构:
//转化为Map集合 List> mapList = BeanMapUtils.listBeanToListMap(nodePOs); //获取树形结构 List > java7ResultTree = getJava7ResultTree(mapList); //打印输出 System.out.println(JSON.toJSONString(java7ResultTree));
打印结果:
[{“orderNo”:”_0001″,”children”:[{“orderNo”:”_0002″,”children”:[],”name”:”二级节点1.1″,”id”:”2″,”parentId”:”1″},{“orderNo”:”_0003″,”children”:[],”name”:”二级节点1.2″,”id”:”3″,”parentId”:”1″}],”name”:”一级节点1″,”id”:”1″},{“orderNo”:”_0004″,”children”:[{“orderNo”:”_0005″,”children”:[],”name”:”二级节点2.1″,”id”:”5″,”parentId”:”4″},{“orderNo”:”_0006″,”children”:[{“orderNo”:”_0007″,”children”:[],”name”:”三级节点2.2.1″,”id”:”7″,”parentId”:”6″}],”name”:”二级节点2.2″,”id”:”6″,”parentId”:”4″}],”name”:”一级节点2″,”id”:”4″},{“orderNo”:”_0008″,”children”:[{“orderNo”:”_0009″,”children”:[{“orderNo”:”_0010″,”children”:[{“orderNo”:”_0011″,”children”:[{“orderNo”:”_0012″,”children”:[],”name”:”五级节点3.1.1.1.1″,”id”:”12″,”parentId”:”11″}],”name”:”四级节点3.1.1.1″,”id”:”11″,”parentId”:”10″}],”name”:”三级节点3.1.1″,”id”:”10″,”parentId”:”9″}],”name”:”二级节点3.1″,”id”:”9″,”parentId”:”8″}],”name”:”一级节点3″,”id”:”8″}]
树形结构搞定!
3.2、Java8及以上借助lamda表达式实现
Java7的方式虽然实现了树形结构,但是有一定的缺点,比如:代码量比较大,逻辑相对较复杂,那Java8是如何简化,如下所示:
既然Java8有lamda表达式,那代码我们能省就省,先看排序,一行代码搞定:
/**
* 根据orderNo排序树形结构的每一个层级
* @param list
* @return
*/
public static List> sortJava8Map(List> list){
if(CollectionUtils.isEmpty(list)){
return Lists.newArrayList();
}
//关键之处,一行代码搞定
list.sort(Comparator.comparing(m -> String.valueOf(m.get("orderNo"))));
return list;
}
给定一个节点,获取它的所有子节点:
释义:
filter: 过滤,相当于for循环,再if条件判断。
peek: 给定一个节点,往它的children塞子节点。
/**
* 根据父级节点获取所有的子集节点
* @param parentNode
* @param allList
* @return
*/
public static List> getJava8Children(Map parentNode, List> allList){
return allList.stream()
.filter(curNode -> ObjectUtils.isNotEmpty(curNode.get("parentId")) && Objects.equals(curNode.get("parentId"),parentNode.get("id")))
.peek(m -> m.put("children", getJava8Children(m,allList))).collect(Collectors.toList());
}
给出一个结果集,构建树形结果集:
/**
* 获取树形结构
* @param mapList
* @return treeList 树形结果集
*/
public static List> getJava8ResultTree(List> mapList){
if (CollectionUtils.isEmpty(mapList)){
return Lists.newArrayList();
}
//filter过滤出所有的一级节点
return mapList.stream().filter(m -> Objects.equals(m.get("parentId"), null) || Objects.equals(m.get("parentId"), ""))
.peek(m -> m.put("children", sortJava8Map(getJava8Children(m, mapList)))).collect(Collectors.toList());
}
获取树形结构:
//转化为Map集合 List> mapList = BeanMapUtils.listBeanToListMap(nodePOs); //获取树形结构 List > java8ResultTree = getJava8ResultTree(mapList); //打印输出 System.out.println(JSON.toJSONString(java8ResultTree));
打印结果:
[{“orderNo”:”_0001″,”children”:[{“orderNo”:”_0002″,”children”:[],”name”:”二级节点1.1″,”id”:”2″,”parentId”:”1″},{“orderNo”:”_0003″,”children”:[],”name”:”二级节点1.2″,”id”:”3″,”parentId”:”1″}],”name”:”一级节点1″,”id”:”1″},{“orderNo”:”_0004″,”children”:[{“orderNo”:”_0005″,”children”:[],”name”:”二级节点2.1″,”id”:”5″,”parentId”:”4″},{“orderNo”:”_0006″,”children”:[{“orderNo”:”_0007″,”children”:[],”name”:”三级节点2.2.1″,”id”:”7″,”parentId”:”6″}],”name”:”二级节点2.2″,”id”:”6″,”parentId”:”4″}],”name”:”一级节点2″,”id”:”4″},{“orderNo”:”_0008″,”children”:[{“orderNo”:”_0009″,”children”:[{“orderNo”:”_0010″,”children”:[{“orderNo”:”_0011″,”children”:[{“orderNo”:”_0012″,”children”:[],”name”:”五级节点3.1.1.1.1″,”id”:”12″,”parentId”:”11″}],”name”:”四级节点3.1.1.1″,”id”:”11″,”parentId”:”10″}],”name”:”三级节点3.1.1″,”id”:”10″,”parentId”:”9″}],”name”:”二级节点3.1″,”id”:”9″,”parentId”:”8″}],”name”:”一级节点3″,”id”:”8″}]
树形结构搞定!两种实现方式对比一下,你就说Java8的方式哇塞不哇塞!!!
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