mysql排名的三种常见方式

三种常见的排名

row_number、dense_rank、rank在MySQL 5.7中的实现

准备数据

表结构说明

成绩表 SC(SId,CId,score)

  • SId 学⽣编号
  • CId 课程编号
  • score 分数

创建SC表

1
2
3
4
5
create table SC(
    SId varchar(10),
    CId varchar(10),
    score decimal(18,1)
);

插入数据

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
-- 成绩表 SC
insert into SC values('01' , '01' , 80);
insert into SC values('01' , '02' , 90);
insert into SC values('01' , '03' , 99);
insert into SC values('02' , '01' , 70);
insert into SC values('02' , '02' , 60);
insert into SC values('02' , '03' , 80);
insert into SC values('03' , '01' , 80);
insert into SC values('03' , '02' , 80);
insert into SC values('03' , '03' , 80);
insert into SC values('04' , '01' , 50);
insert into SC values('04' , '02' , 30);
insert into SC values('04' , '03' , 20);
insert into SC values('05' , '01' , 76);
insert into SC values('05' , '02' , 87);
insert into SC values('06' , '01' , 31);
insert into SC values('06' , '03' , 34);
insert into SC values('07' , '02' , 89);
insert into SC values('07' , '03' , 98);

对SC中的学生score进行整体排名

ROW_NUMBER

1 2 3 4 5 6 7 没有重复排名,依次递增

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
SET @i := 0;
SET @p := 0;
SET @q := 0;
SELECT  t1.SId
        ,t1.CId
        ,t1.score
        ,@p := t1.score
        ,if(@p=@q,@i,@i := @i+1) as dense_rank
        ,@q :=@p
from (
    SELECT  SId
            ,CId
            ,score
    from SC
    order by score desc
) t1;

DENSE_RANK

1 2 3 3 3 4 5 6 7 有重复时并列排名,最终排名也是连续的

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
SET @i := 0;
SET @p := 0;
SET @q := 0;
SELECT  t1.SId
        ,t1.CId
        ,t1.score
        ,@p := t1.score
        ,if(@p=@q,@i,@i := @i+1) as dense_rank
        ,@q :=@p
from (
    SELECT  SId
            ,CId
            ,score
    from SC
    order by score desc
) t1;

RANK

1 2 3 3 3 6 7 8 有重复时并列排名,最终排名不连续

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
SET @i := 0;
SET @j := 0;
SET @p := 0;
SET @q := 0;
SELECT  t1.SId
        ,t1.CId
        ,t1.score
        ,@j := @j + 1
        ,@p := t1.score
        ,if(@p=@q,@i,@i := @j) as rank
        ,@q :=@p
from (
    SELECT  SId
            ,CId
            ,score
    from SC
    order by score desc
) t1;

进行分组排名

ROW_NUMBER

查询每⻔课程成绩最好的前三名 1 2 3 4 5 6 7 没有重复排名,依次递增

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
SET @i := 0;
SET @p := 0;
SET @q := 0;
SELECT  tt1.SId
        ,tt2.SName
        ,tt1.CId
        ,tt1.score
        ,tt1.rn
from (
    select  t1.SId
            ,t1.CId
            ,t1.score
            ,@p := t1.CId
            ,if(@p=@q,@i := @i + 1,@i :=1) as rn
            ,@q := @p
    from (
        select  SId
                ,CId
                ,score
        from SC
        order by CId,score DESC
    ) t1
) tt1 join Student tt2 on tt1.rn

DENSE_RANK

查询每⻔课程成绩最好的前三名 1 2 3 3 3 4 5 6 7 有重复时并列排名,最终排名也是连续的

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
SET @i := 0;
SET @p := 0;
SET @q := 0;
SET @j := 0;
SET @k := 0;
SELECT  tt1.SId
        ,tt2.SName
        ,tt1.CId
        ,tt1.score
        ,tt1.rn
from (
    select  t1.SId
            ,t1.CId
            ,t1.score
            ,@p := t1.CId
            ,@j := t1.score
            ,if(@p=@q,if(@j=@k,@i,@i := @i + 1),@i :=1) as rn
            ,@q := @p
            ,@k := @j
    from (
        select  SId
                ,CId
                ,score
        from SC
        order by CId,score DESC
    ) t1
) tt1 join Student tt2 on tt1.rn

RANK

查询每⻔课程成绩最好的前三名 1 2 3 3 3 6 7 8 有重复时并列排名,最终排名不连续

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
SET @i := 0;
SET @p := 0;
SET @q := 0;
SET @j := 0;
SET @k := 0;
SET @m := 1;
SELECT  tt1.SId
        ,tt2.SName
        ,tt1.CId
        ,tt1.score
        ,tt1.rn
from (
    select  t1.SId
            ,t1.CId
            ,t1.score
            ,@p := t1.CId
            ,@j := t1.score
            ,if(@p=@q,@m := @m + 1,@m := 1)
            ,if(@p=@q,if(@j=@k,@i,@i := @m),@i :=1) as rn
            ,@q := @p
            ,@k := @j
    from (
        select  SId
                ,CId
                ,score
        from SC
        order by CId,score DESC
    ) t1
) tt1 join Student tt2 on tt1.rn

总结

以上为个人经验,希望能给大家一个参考,也希望大家多多支持IT俱乐部。

本文收集自网络,不代表IT俱乐部立场,转载请注明出处。https://www.2it.club/database/mysql/11403.html
上一篇
下一篇
联系我们

联系我们

在线咨询: QQ交谈

邮箱: 1120393934@qq.com

工作时间:周一至周五,9:00-17:30,节假日休息

关注微信
微信扫一扫关注我们

微信扫一扫关注我们

返回顶部